5x^2+25x-160=180

Solution for 5x^2+25x-160=180 equation:

5x^2+25x-160=180

We move all terms to the left:

5x^2+25x-160-(180)=0

We add all the numbers together, and all the variables

5x^2+25x-340=0

a = 5; b = 25; c = -340;
Δ = b2-4ac
Δ = 252-4·5·(-340)
Δ = 7425
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7425}=\sqrt{225*33}=\sqrt{225}*\sqrt{33}=15\sqrt{33}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-15\sqrt{33}}{2*5}=\frac{-25-15\sqrt{33}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+15\sqrt{33}}{2*5}=\frac{-25+15\sqrt{33}}{10}
$